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    Topics || Problems

    Find the range of value of b if \(2x^2 +bx +8 = 0\) has no real roots. Express your answer in interval.

    Solution:

    • No real roots; the discriminant is less than zero.

    • \( b^2 -4ac < 0 \)

    • \(b^2 - 4(2)(8) \)< 0

    • b < 8

    • b > -8
    • Values of b: [-8, 8]